MHT CET202020 Oct 2020Evening ShiftPhysicsDual Nature of MatterActual
Photoelectrons are emitted from a photosensitive surface for the light of wavelengths ₁=360 ~nm and ₂=600 ~nm . What is the ratio of work functions for lights of wavelength ^ ₁ ^ to ₂ ^ ?
Options
- A6: 1
- B1: 6
- C5: 3
- D3: 5
Correct answer
C. 5: 3
Step-by-step solution
h c ₁ - ₁= KE ₁=360 ~nm =360 10⁻⁹ ~m hc ₂ - ₂= KE ₂=600 ~nm =600 10⁻⁹ ~m h c ₁ = ₁ 1 ₁ ₂ = ₂ ₁ = 600 360 = 10 6 = 5 3