MHT CET202617 April 2026Evening ShiftPhysicsKinetic Theory of GasesActual
The temperature at which r.m.s. velocity of hydrogen molecules is 4.5 times that of an oxygen molecule at 47^ C is (molecular weight of hydrogen and oxygen are 2 and 32 respectively)
Options
- A47^ C
- B132^ C
- C320^ C
- D405^ C
Correct answer
B. 132^ C
Step-by-step solution
The r.m.s. velocity of a gas molecule is given by v_ rms = 3RT M Given v_ rms (H₂) = 4.5 v_ rms (O₂) 3 R T_ H₂ M_ H₂ = 4.5 3 R T_ O₂ M_ O₂ Squaring both sides, we get: T_ H₂ M_ H₂ = (4.5)^2 T_ O₂ M_ O₂ Given M_ H₂ = 2 , M_ O₂ = 32 , and T_ O₂ = 47^ C = 320 K T_ H₂ 2 = 20.25 320 32 T_ H₂ 2 = 20.25 10 = 202.5 T_ H₂ = 405 K Converting to Celsius: T_ H₂ = 405 - 273 = 132^ C Answer: 132^ C