The heat energy that must be supplied to 14 g of nitrogen at room temperature to raise its temperature by 48 ^ C at constant pressure is ( R = gas constant, Molecular weight of nitrogen ( N ₂) = 28)

Step-by-step solution

Number of moles of nitrogen gas, n = m M = 14 28 = 0.5 Nitrogen is a diatomic gas, so its molar heat capacity at constant pressure is C_p = 7 2 R Heat energy supplied at constant pressure is given by Q = n C_p T Substituting the given values: Q = 0.5 7 2 R 48 Q = 1 2 7 2 R 48 Q = 7 4 R 48 = 84 R Answer: 84 R