MHT CET202613 April 2026Evening ShiftPhysicsKinetic Theory of GasesActual
Let ₁ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a mono-atomic gas and ₂ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, ₁ / ₂ is
Options
- A27/35
- B35/27
- C25/21
- D21/25
Correct answer
C. 25/21
Step-by-step solution
For a mono-atomic gas, the number of degrees of freedom is f₁ = 3 . The ratio of specific heats is ₁ = 1 + 2 f₁ = 1 + 2 3 = 5 3 . For a diatomic gas acting as a rigid rotator, the number of degrees of freedom is f₂ = 5 (3 translational and 2 rotational). The ratio of specific heats is ₂ = 1 + 2 f₂ = 1 + 2 5 = 7 5 . The required ratio is ₁ ₂ = 5/3 7/5 = 25 21 . Answer: 25/21