In case of gas, as shown in P-T graph, the densities at points A and B are ₀ and 4 3 ₀ respectively. The value of Y on pressure ( P ) axis is

Step-by-step solution

Using the ideal gas equation PV = nRT and substituting n = m M yields PV = m M RT . Rearranging for density = m V gives P = RT M . For a fixed molar mass M , the ratio P T = R M remains constant. Applying this to points A and B: At point A: P₀ ₀ T₀ = R M At point B: Y ( 4 3 ₀)(3T₀) = R M Equating both expressions: P₀ ₀ T₀ = Y 4 ₀ T₀ Solving for Y gives Y = 4P₀ . Final answer: 4P₀