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MHT CET202519 Apr 2025Evening ShiftPhysicsKinetic Theory of GasesActual

Two gases A and B are at absolute temperatures 350 K and 420 K respectively. The ratio of average kinetic energy of the molecules of gas B to that of gas A is

Options

  1. A6: 5
  2. B6 : 5
  3. C36: 25
  4. D5: 6

Correct answer

A. 6: 5

Step-by-step solution

The average kinetic energy for an ideal gas is given by KE_ avg = 3 2 kT , where T is the absolute temperature. For gases A and B with temperatures T_A = 350 K and T_B = 420 K , the ratio of kinetic energies simplifies to: KE_ avg,B KE_ avg,A = T_B T_A = 420 350 Reducing this fraction yields: 420 350 = 42 35 = 6 5 The ratio of average kinetic energy of gas B to gas A is therefore 6:5 . Final answer: A

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