MHT CET202416 May 2024Morning ShiftPhysicsKinetic Theory of GasesActual
Assuming the expression for the pressure exerted by the gas, it can be shown that pressure is
Options
- A( 3 4 )^ th of kinetic energy per unit volume of a gas.
- B( 2 3 )^ rd of kinetic energy per unit volume of a gas.
- C( 1 3 )^ rd of kinetic energy per unit volume of a gas.
- D( 3 2 )^ rd of kinetic energy per unit volume of a gas.
Correct answer
B. ( 2 3 )^ rd of kinetic energy per unit volume of a gas.
Step-by-step solution
Pressure exerted by the gas on wall of container is given by, aligned P & = 1 3 v^2 P & = 1 3 ( M V ) v^2 aligned ( v = r.m.s. speed ) Dividing and multiplying equation by 2 , aligned & P= 2 3 1 2 ( M V ) v^2 & (V= 2 3 ( Volume of the gas ) V ) . & ( K.E. = 1 2 M v^2 ) aligned