A piece of metal weighing 100 ~g is heated to 80^ C and dropped into 1 ~kg of cold water in an insulated container at 15^ C . If the final temperature of the water in the container is 15.69^ C , the specific heat of the metal in J / g ^ C is:

Step-by-step solution

Heat exchanged is given by, Q = m s ( T ₂- T ₁ ) where s = specific heat So, when heated metal is dropped into the cold water, we can write: aligned & m _ metal s _ metal ( T ₂- T ₁ )_ metal = m _ water s _ water ( T ₂- T ₁ )_ water & 0.1 s _ metal (80-15.69)=1 4.18 (15.69-15) & s _ metal =0.45 ~J / g ^ C aligned