Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET2019Evening ShiftPhysicsKinetic Theory of GasesActual

The equation of state or 2g of oxygen at a pressure ‘P’ and temperature ‘T’, when occupying a volume ‘V’ will be

Options

  1. Ap V = 16 R T
  2. Bp V = R T
  3. Cp V = 1 16 R T
  4. Dp V = 2 R T

Correct answer

C. p V = 1 16 R T

Step-by-step solution

The ideal gas equation is given by p V = μ R T where, μ = number of moles in gas As, μ = G i v e n m a s s M o l e c u l a r m a s s = m M Here, m = 2g And for oxygen O 2 , M = 32 g Substituting these values in Eq. (i), we get p V = m M R T = 3 32 R T ∴ p V = 1 16

Practice Kinetic Theory of Gases on Quantrex Academy →

More from Kinetic Theory of Gases

A vessel of volume 27 10^4 cc, contains a mixture of Hydrogen (molar mass = 2 g mol⁻¹ ) and oxygen (molar mass = 32 g mol⁻¹ ) gas at standard temperature and pressure. If the mass 2026Find the mass of oxygen gas with which 1.882 10²³ degrees of freedom are associated at N.T.P. Given: Molar mass of diatomic gas, oxygen is 32 g mol⁻¹ and oxygen molecule possess th 2026An ideal gas has molar specific heat 5R 2 at constant pressure. If 1662 J of heat brings about 50 K temperature change, the number of moles of gas is 2026A jar is filled with two monoatomic non-interacting gases A and B with total masses M_A and M_B , respectively. The molar mass of A is double the molar mass of B . If the jar is ke 2026The graph of pressure P and volume V of 1 mole of an ideal gas at constant temperature is 2026Gas at pressure P, temperature T, and volume V is filled in jar A. Another jar B is filled with gas having parameters 2P , V 4 , 2T . The ratio of number of molecules of jar B to t 2026An ideal gas ( = 1.5 ) is expanded adiabatically. To reduce the root mean square velocity of molecules two times, the gas should be expanded 2026Assuming the expression for the pressure exerted by the gas, it can be shown that pressure is 2026 Full Kinetic Theory of Gases list All MHT CET PYQs