An open U-tube contains mercury. When 11.2 ~cm of water is poured into one of the arms of the tube, how high does the mercury rise in the other arm from its initial unit?

Step-by-step solution

On pouring water on left side, mercury rises x cm (say) from its previous level in the right limb of U-tube creating a difference of levels of mercury by 2 x ~cm . Equating pressure at A and B , we get array l p_ A =p_ B 11.2 10⁻² _ water g=2 x _ Hg g 11.2 10⁻² 1000 ~kg / m ³ =2 x 13600 ~kg / m ³ x= 11.2 10⁻² 1000 2 13600 ~m =0.41 ~cm array