A car of mass m is crossing the convex bridge of radius of curvature R with speed V. At the highest point the thrust is ( g = gravitational acceleration)

Step-by-step solution

At the highest point of the convex bridge, the forces acting on the car are its weight mg acting downwards and the normal reaction N acting upwards. The net force towards the center of the circular path provides the necessary centripetal force. mg - N = mv^2 R N = mg - mv^2 R The thrust exerted by the car on the bridge is equal in magnitude to the normal reaction N . Answer: mg - mv^2 R