MHT CET202523 Apr 2025Morning ShiftPhysicsLaws of MotionActual
The figure shows two masses ' m ' and ' M ' connected by a light string that passes through a small hole 'O' at the centre of the table. Mass ' m ' is moved round in a horizontal circle with 'O' as the centre. The frequency with which ' m ' should be revolved so that ' M ' remains stationary is (g = gravitational acceleration)
Options
- A1 ML mg
- B1 2 Mg mL
- C1 Mg mL
- D1 2 ML mg
Correct answer
B. 1 2 Mg mL
Step-by-step solution
Equilibrium requires that the tension force matches the weight of mass M : T = Mg . The centripetal force for mass m revolving with angular frequency at radius L is provided by tension: T = m ^2 L . Equating gives Mg = m ^2 L . Substituting = 2 f yields Mg = m (2 f)^2 L = 4 ^2 m f^2 L . Solving for frequency: f = 1 2 Mg mL .