Two blocks of masses 6 kg and 4 kg are placed in contact with each other on a smooth surface as shown. If a force of 5 N is applied on a heavier block, the force on the lighter block is

Step-by-step solution

Given: m ₁=6 ~kg , ~m ₂=4 ~kg and F =5 ~N array ll & F= (m₁+m₂ ) a & a= F (m₁+m₂ ) = 5 (6+4) =0.5 ~m / s ^2 array aligned Force on second mass & = m ₂ a & =4 0.5 . & =2 ~N aligned