MHT CET20242 May 2024Evening ShiftPhysicsLaws of MotionActual
The mass of the lift is 200 kg , when it ascends with an acceleration of 4 ~m / s ^2 then the tension in the cable supporting the lift will be [Given: Acceleration due to gravity .g=10 ~m / s ^2 ]
Options
- A800 N
- B2800 N
- C4200 N
- D2000 N
Correct answer
B. 2800 N
Step-by-step solution
The equation of motion for the lift is: aligned & T - ma = mg & ~T = m ( ~g + a ) & =200(10+4) & T =2800 ~N aligned