MHT CET202313 May 2023Evening ShiftPhysicsLaws of MotionActual
A mass ' M ' is suspended from a light spring. An additional mass M ₁ added extends the spring further by a distance ' x '. Now the combined mass will oscillate on the spring with period T =
Options
- A2 [ ( M₁ g x (M+M₁ ) ) ]^ 1 2
- B2 [ ( M + M ₁ ) x M ₁ ~g ]^ 1 2
- C( 2 ) [ ( M₁ g x (M+M₁ ) ) ]^ 1 2
- D2 [ ( M + M ₁ ) x M ₁ ~g ]^ 1 2
Correct answer
B. 2 [ ( M + M ₁ ) x M ₁ ~g ]^ 1 2
Step-by-step solution
Time period T=2 m k Here, k x=M₁ g K = M ₁ ~g x Combined mass: M + M ₁ T =2 x ( M + M ₁ ) M ₁ ~g