MHT CET202310 May 2023Morning ShiftPhysicsLaws of MotionActual
A body of mass 200 gram is tied to a spring of spring constant 12.5 ~N / m , while other end of spring is fixed at point ' O '. If the body moves about ' O ' in a circular path on a smooth horizontal surface with constant angular speed 5 rad / s then the ratio of extension in the spring to its natural length will be
Options
- A1: 2
- B1:1
- C2:3
- D2:5
Correct answer
C. 2:3
Step-by-step solution
Let the normal length be L and the extension be x . Restoring Force = Centripetal Force aligned & kx = m ( L + x ) ^2 & 12.5 x =0.2( ~L + x ) 25 ( =5 rad / s ) aligned aligned & 12.5 x=5(L+x) & 7.5 x=5 L & x L = 5 7.5 = 2 3 =2: 3 aligned