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MHT CET202210 Aug 2022Evening ShiftPhysicsLaws of MotionActual

Two massless springs of spring constant K₁ and K₂ are connected one after the other forming a single chain, suspended vertically and certain mass is attached to the free end. If e₁ and e₂ are their respective extensions and f is their stretching force, the total extension produced is

Options

  1. Af (K₁-K₂ )
  2. Bf ( rac 1 K₁ - 1 K₂ )
  3. Cf (K₁+K₂ )
  4. Df ( 1 K₁ + 1 K₂ )

Correct answer

D. f ( 1 K₁ + 1 K₂ )

Step-by-step solution

The total restoring force is related to extension as follows: f=-K x ---(1) The extension in the springs are related to the restoring force as follows: f=-K₁ e₁---(2) and f=-K₂ e₂---(3) The total extension of the springs is: x=e₁+e₂---(4) Using equation (1),(2) and (3) aligned & (- f K )= (- f K₁ )+ (- f K₂ ) & 1 K = ( 1 K₁ + 1 K₂ )---(5) aligned The total extension using equation (4) and (5)is given by, x= f K =f ( 1 K₁ + 1 K₂ )

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