A block of mass 'M' is moving on rough horizontal surface with momentum 'P'. The coefficient of friction between the block and surface is ' '. The distance covered by block before it stops is [ g = acceleration due to gravity ]

Step-by-step solution

Using kinematic relation, v²=u²-2 a s The momentum pis given by array l p=M u u= P M array and acceleration is given as a= g Substituting values in Eq. (i), we get array l 0= u 2-2 as ( f alvelocity , v=0) 0= ( p M )²-2 gs ( p M )²=2 gs s = p ² 2 M ² g array