MHT CET20192 May 2019Morning ShiftPhysicsLaws of MotionActual
A stone of mass 1 k g is tied to a string 2 m long and is rotated at a constant speed of 40 m s - 1 in a vertical circle. The ratio of the tension at the top and the bottom is [Take g = 10 m s - 2 ]
Options
- A81 79
- B79 81
- C19 12
- D12 19
Correct answer
B. 79 81
Step-by-step solution
T t o p + m g = m v 2 R ⇒ T t o p = 1 40 2 2 - 1 10 = 790 N T B o t - m g = m v 2 R ⇒ T B o t = 1 40 2 2 + 1 10 = 810 N T t o p T B o t = 790 810 = 79 81