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MHT CET2011PhysicsLaws of Motion

A car of mass 1500 ~kg is moving with a speed of 12.5 ~m / s on a circular path of radius 20 ~m on a level road. What should be the coefficient of friction between the car and the road, so that the car does not slip?

Options

  1. A0.2
  2. B0.4
  3. C0.6
  4. D0.8

Correct answer

D. 0.8

Step-by-step solution

In this case centripetal force provides by friction m v² r = m g i. e , = v² r g = 12.5 12.5 20 9.8 =0.8

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