The region inside a current carrying toroid is filled with a material (Niobium) having susceptibility = 2.6 10⁻⁵ . The percentage increase in the magnetic field in the presence of Niobium over that without it, is

Step-by-step solution

The magnetic field inside a toroid without any material is given by B₀ = ₀ n I . When the toroid is filled with a material of magnetic susceptibility , the magnetic field becomes B = ₀ (1 + ) n I . The increase in the magnetic field is B = B - B₀ = ₀ n I = B₀ . The percentage increase in the magnetic field is B B₀ 100 = 100 . Substituting the given value of susceptibility = 2.6 10⁻⁵ : Percentage increase = 2.6 10⁻⁵ 100 = 2.6 10⁻³ . Answer: 2.6 10⁻³