The magnetization of bar magnet of length 5 cm, cross sectional area 2 c m 2 and net magnetic moment 1 A m 2 is

Step-by-step solution

Given, l = 5 c m = 5 × 10 - 2 m , a = 2 c m 2 = 2 × 10 - 4 m 2 And M = 1 A m - 2 The magnetisation of the bar magnet is given by l = M V where, V = volume of bar magnet = a × l ⇒ l = M a × l Substituting given values, we get l = 1 2 × 10 - 4 × 5 × 10 - 2 = 1 10 - 5 = 1 × 10 5 A m