The momentum of a photon of energy 1 MeV in kg - m / s , will be

Step-by-step solution

Energy of photon is given by E= h c where h is the Planck's constant, c the velocity of light and its wavelength. de-Broglie wavelength is given by = h p where p is being momentum of photon. From Eqs. (i) and (ii), we get E= h c h / p =p c Or p=E / c Given, aligned &=1 MeV =1 10⁶ 1.6 10⁻¹⁹ ~J , c &=3 10⁸ ~m / s aligned Hence, after putting numerical values, we obtain aligned p &= 1 10⁶ 1.6 10⁻¹⁹ 3 10⁸ ~kg - m / s &=5 10⁻²² ~kg - m / s aligned