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MHT CET202620 April 2026Evening ShiftPhysicsOscillationsActual

The displacement of a particle varies with time according to the relation x = a t + b t

Options

  1. AThe motion is simple harmonic motion with an amplitude [3] a^2 + b^2
  2. BThe motion is simple harmonic motion with an amplitude a^2 + b^2
  3. CThe motion is periodic but not simple harmonic motion
  4. DThe motion is simple harmonic with an amplitude (a^2 + b^2)

Correct answer

B. The motion is simple harmonic motion with an amplitude a^2 + b^2

Step-by-step solution

Given displacement is x = a t + b t Multiplying and dividing by a^2 + b^2 , we get x = a^2 + b^2 ( a a^2 + b^2 t + b a^2 + b^2 t ) Let = a a^2 + b^2 and = b a^2 + b^2 x = a^2 + b^2 ( t + t ) x = a^2 + b^2 ( t + ) This represents a simple harmonic motion with amplitude A = a^2 + b^2 . Answer: The motion is simple harmonic motion with an amplitude a^2 + b^2

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