A spring force constant 180 N/m is loaded with a mass 0.2 kg. The amplitude of oscillations is 4 cm. When mass comes to equilibrium position, its velocity is

Step-by-step solution

Given k = 180 N/m, m = 0.2 kg, and A = 4 cm = 0.04 m. The angular frequency of the spring-mass system is given by: = k m Substituting the given values: = 180 0.2 = 900 = 30 rad/s The velocity of the mass at the equilibrium position is its maximum velocity, which is given by: v_ max = A v_ max = 0.04 30 = 1.2 m/s Answer: 1.2 m/s