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MHT CET202618 April 2026Evening ShiftPhysicsOscillationsActual

Two particles A and B of equal masses are suspended from two massless springs of spring constants K_A and K_B respectively. The maximum velocities of the particles during oscillations are equal. The ratio of the amplitude of 'B' to that of 'A' is

Options

  1. AK_A : K_B
  2. BK_A : K_B
  3. CK_B : K_A
  4. DK_B : K_A

Correct answer

B. K_A : K_B

Step-by-step solution

Let the masses of the particles be m . The angular frequencies of oscillations for particles A and B are _A = K_A m and _B = K_B m . The maximum velocity of a particle in simple harmonic motion is given by v_ max = A , where A is the amplitude. Given that the maximum velocities are equal: A_A _A = A_B _B A_A K_A m = A_B K_B m A_A K_A = A_B K_B A_B A_A = K_A K_B The ratio of the amplitude of B to that of A is K_A : K_B . Answer: K_A : K_B

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