Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202615 April 2026Evening ShiftPhysicsOscillationsActual

A pendulum clock is running slow, In order to correct it, we should

Options

  1. Areduce the amplitude of oscillation.
  2. Breduce the mass of the bob.
  3. Creduce the length of pendulum.
  4. Dincrease the length of pendulum.

Correct answer

C. reduce the length of pendulum.

Step-by-step solution

The time period of a simple pendulum is given by T = 2 l g . If the pendulum clock is running slow, it means its time period T is greater than the correct value. To correct the clock, the time period T must be decreased. Since T l , decreasing the length l of the pendulum will decrease the time period T . Therefore, the length of the pendulum should be reduced. Answer: reduce the length of pendulum.

Practice Oscillations on Quantrex Academy →

More from Oscillations

Force constant of interatomic bond, in a certain element, is 7.1 Nm⁻¹ . If the atom oscillates in SHM in a certain direction, what is its frequency? Given: Mole weight of the given 2026An object of mass 10g executes SHM along the x -axis with frequency of ( 10 ) Hz. At the point x = 2 cm the object has KE 1.2 J and PE 0.4 J. The amplitude of oscillation is 2026A simple pendulum of length L , mass m and electric charge q on its bob is oscillating with a time period T under uniform gravity which is in the - z direction. Upon applying a uni 2026A sphere and a cube of equal masses on a horizontal frictionless floor, are confined between two vertical walls, as shown in the figure. The cube is attached to the wall by a massl 2026A mass of 1 kg is executing SHM. Its displacement is given by x = 6.0 (100t + /4) cm. What is the maximum kinetic energy? 2026If the displacement of a particle executing simple harmonic motion is given by x =0.5 (125.6 t ) , then the time period of oscillation of the particle is nearly (Here x is displace 2025The amplitude of a damped harmonic oscilator becomes 50 % of its initial value in a time of 12 s. If the amplitude of the oscillator at a time of 36 s is x % of its initial amplitu 2025If the function ^2 t ( t is time in second) represents a periodic motion, then the period of the motion is 2025 Full Oscillations list All MHT CET PYQs