The minimum phase difference between two simple harmonic motions is x₁ = 1 2 t + 1 2 t x₂ = t + t [ 4 = 4 = 1 2 ]

Step-by-step solution

The given equations of simple harmonic motion are: x₁ = 1 2 t + 1 2 t x₁ = t 4 + t 4 = ( t + 4 ) x₂ = t + t x₂ = 2 ( 1 2 t + 1 2 t ) = 2 ( t + 4 ) The phase of x₁ is ₁ = 4 and the phase of x₂ is ₂ = 4 . Phase difference = ₁ - ₂ = 4 - 4 = 0 .