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MHT CET202615 April 2026Evening ShiftPhysicsOscillationsActual

A body of mass 0.4 kg performs simple harmonic motion. It experiences a restoring force of 0.4 N when its displacement from the mean position is 4 cm. The force constant and magnitude of acceleration respectively are

Options

  1. A5 N/ _ m , 0.5 m/ _ s ^2
  2. B10 N/ _ m , 1 m/ _ s ^2
  3. C15 N/ _ m , 1.5 m/ _ s ^2
  4. D20 N/ _ m , 2 m/ _ s ^2

Correct answer

B. 10 N/ _ m , 1 m/ _ s ^2

Step-by-step solution

Given m = 0.4 kg, F = 0.4 N, and x = 4 cm = 0.04 m. The force constant k is given by the relation F = kx . k = F x = 0.4 0.04 = 10 N/m. The magnitude of acceleration a at this displacement is given by Newton's second law, F = ma . a = F m = 0.4 0.4 = 1 m/s ^2 . Answer: 10 N/ _ m , 1 m/ _ s ^2

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