A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 1.6 m. The period of Oscillation of the sphere is (Acceleration due to gravity g = 10 m/s ^2 )

Step-by-step solution

The oscillation of a small sphere in a watch glass of radius of curvature R is equivalent to a simple pendulum of effective length R . The time period of oscillation is given by T = 2 R g . Given R = 1.6 m and g = 10 m/s ^2 . Substituting the values: T = 2 1.6 10 T = 2 0.16 T = 2 0.4 = 0.8 s. Answer: 0.8