A particle is performing S.H.M. starting from extreme position. Graphical representation shows that between displacement and acceleration, there is a phase difference of

Step-by-step solution

Displacement and acceleration phase difference in SHM For a particle in simple harmonic motion starting from an extreme position, the displacement is given by x = A ( t) with initial phase = 0 . Differentiating twice gives the acceleration: a = d^2x dt^2 = -A ^2 ( t) This can be expressed as a = A ^2 ( t + ) , showing a phase shift of radians relative to the displacement x = A ( t) . The negative sign in a = - ^2 x confirms the acceleration is always opposite to displacement, precisely out of phase. Final answer: A