A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 1.6 m . The period of oscillation of the sphere is (acceleration due to gravity g=10 ~m / s ^2 )

Step-by-step solution

The motion of a small sphere oscillating in a watch glass is equivalent to a simple pendulum’s motion, with the effective length equal to the watch glass’s radius of curvature. The period of oscillation is given by T = 2 L g , where L = R = 1.6 m and g = 10 m/s^2 . Substituting these values yields T = 2 1.6 10 = 2 0.16 = 2 0.4 = 0.8 s . This result corresponds to option D .