Two simple harmonic motions of angular frequency 300 rad / s and 3000 rad / s have same amplitude. The ratio of their maximum accelerations is

Step-by-step solution

Maximum acceleration in simple harmonic motion is given by a_ max = A ^2 , where A is the amplitude and is the angular frequency. Given identical amplitudes A₁ = A₂ = A and angular frequencies ₁ = 300 rad/s , ₂ = 3000 rad/s , the ratio of maximum accelerations is: a_ max ,1 a_ max ,2 = A ₁^2 A ₂^2 = (300)^2 (3000)^2 = ( 1 10 )^2 = 1 100 This corresponds to ratio 1:10^2 , making option B correct. Final answer: B