MHT CET202520 Apr 2025Morning ShiftPhysicsOscillationsActual

The period of S.H.M. of a particle is 16 second. The phase difference between the positions at t =2 ~s and t =4 ~s will be

Options

Correct answer

C. 8

Step-by-step solution

Phase difference in SHM for given times Given the period T = 16 s , angular frequency is = 2 T = 8 rad/s . With times t₁ = 2 s and t₂ = 4 s , the time difference is t = t₂ - t₁ = 2 s . The phase difference is then = t = 8 2 = 4 rad . The phase difference is 4 rad , corresponding to choice C.

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