For a particle performing S.H.M. the displacement - time graph is shown. For that particle the force - time graph is correctly shown in graph

Step-by-step solution

For a particle in simple harmonic motion with displacement y(t) = A ( t) starting from maximum positive displacement at t=0 , the force can be derived from the relationship between acceleration and displacement. The restoring force is given by Newton's second law using the standard S.H.M. acceleration expression a = - ^2 y . Substituting yields F = m(- ^2 y) = -m ^2 y . Inserting the displacement function gives F(t) = -m ^2 A ( t) . Letting F_ max = m ^2 A , this simplifies to F(t) = -F_ max ( t) . This describes a