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MHT CET202416 May 2024Evening ShiftPhysicsOscillationsActual

The kinetic energy of a particle, executing simple harmonic motion is 16 J when it is in mean position. If amplitude of motion is 25 cm and the mass of the particle is 5.12 kg , the period of oscillation is

Options

  1. A5 ~s
  2. B2 ~s
  3. C20 ~s
  4. D5 ~s

Correct answer

A. 5 ~s

Step-by-step solution

Given: K.E. =16 ~J , ~A =25 ~cm =0.25 ~m , m =5.12 ~kg The kinetic energy at mean position is equal to the total energy of the particle. array ll & Total energy, E= 1 2 ~m & ^2= 16 2 5.12 (0.25)^2 =10^2 & =10 & ~T = 2 = 2 10 = 5 ~s array

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