MHT CET202416 May 2024Morning ShiftPhysicsOscillationsActual
A particle executing S.H.M. has velocities ' V ₁ ' and ' V ₂ ' at distances ' x₁ ' and ' x₂ ' respectively, from the mean position. Its frequency is
Options
- A1 2 V₁^2-V₂^2 x₁^2-x₂^2
- B2 x₁^2-x₂^2 V₁^2-V₂^2
- C1 2 V₂^2-V₁^2 x₁^2-x₂^2
- D2 x₁^2-x₂^2 V₂^2-V₁^2
Correct answer
C. 1 2 V₂^2-V₁^2 x₁^2-x₂^2
Step-by-step solution
Particle velocities are aligned & V₁^2= ^2 (A^2-x₁^2 ) ...(i) & V₂^2= ^2 (A^2-x₂^2 )...(ii) aligned Subtracting (i) from (ii), aligned & V₂^2-V₁^2= ^2 (x₁^2-x₂^2 ) & = V₂^2-V₁^2 x₁^2-x₂^2 aligned As =2 f we get, f = 1 2 ~V ₂^2- V ₁^2 x ₁^2- x ₂^2