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MHT CET202411 May 2024Evening ShiftPhysicsOscillationsActual

A piece of wood has length, breadth and height, ' a ', 'b' and ' c ' respectively. Its relative density is ' d '. It is floating in water such that the side ' a ' is vertical. It is pushed down a little and released. The time period of S.H.M. executed by it is ( g= acceleration due to gravity)

Options

  1. A2 a b c g
  2. B2 b c d g
  3. C2 g d a
  4. D2 ad g

Correct answer

D. 2 ad g

Step-by-step solution

Time period of SHM of small vertical oscillations in liquid is given by T =2 l ~g where l is the length of piece of wood Weight of wood = weight of water displaced Mass of wood g = Mass of water displaced g abc d g = bc l 1 g gathered l= da ~T =2 ad ~g gathered ( mass = volume density )

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