A particle performing S.H.M. starts from equilibrium position and its time period is 12 second. After 2 seconds its velocity is m / s . Amplitude of the oscillation is [ 30^ = 60^ =0 5, 60^ = 30^ = 3 / 2 ]

Step-by-step solution

Displacement of the particle, x=A t Velocity of the particle, v = dx dt = A t ...(i) Given that, v = m / s , ~T =12 ~s , = 2 ~T = 6 rad / s Substituting in equation (i), we get, aligned & & = A 6 ( 6 2 ) & 1 & = A 6 ( 3 )= A 6 1 2 & A & =12 ~m aligned