Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202410 May 2024Evening ShiftPhysicsOscillationsActual

A particle performs linear S.H.M. When the displacement of the particle from mean position is 3 cm and 4 cm , corresponding velocities are 8 ~cm / s and 6 ~cm / s respectively. Its periodic time is

Options

  1. A2 ~s
  2. Bs
  3. C3 ~s
  4. D4 ~s

Correct answer

B. s

Step-by-step solution

We have v= A^2-x^2 Substituting the given values in the above equation we get, 8= A^2-9 ...(i) ( x =3 ~cm , v =8 cms ⁻¹ )6= A ^2-16 ...(ii) ( x =4 ~cm , v =6 cms ⁻¹ ) Diving equation (i) and (ii), array ll & 8 6 = A ^2-9 ~A ^2-16 & 4 3 = A ^2-9 ~A ^2-16 & 16 9 = A ^2-9 ~A ^2-16 & 16 ~A ^2-256=9 ~A ^2-81 & 7 ~A ^2=175 & ~A ^2= 175 7 array Substituting this value of A ^2 in equation (ii) and solving we get aligned 6 & = 175 7 -16 6 & = 175-112 7 = 9 6 & =3 & =2 & = 2 T =2 T & = seconds aligned

Practice Oscillations on Quantrex Academy →

More from Oscillations

Force constant of interatomic bond, in a certain element, is 7.1 Nm⁻¹ . If the atom oscillates in SHM in a certain direction, what is its frequency? Given: Mole weight of the given 2026An object of mass 10g executes SHM along the x -axis with frequency of ( 10 ) Hz. At the point x = 2 cm the object has KE 1.2 J and PE 0.4 J. The amplitude of oscillation is 2026A simple pendulum of length L , mass m and electric charge q on its bob is oscillating with a time period T under uniform gravity which is in the - z direction. Upon applying a uni 2026A sphere and a cube of equal masses on a horizontal frictionless floor, are confined between two vertical walls, as shown in the figure. The cube is attached to the wall by a massl 2026A mass of 1 kg is executing SHM. Its displacement is given by x = 6.0 (100t + /4) cm. What is the maximum kinetic energy? 2026If the displacement of a particle executing simple harmonic motion is given by x =0.5 (125.6 t ) , then the time period of oscillation of the particle is nearly (Here x is displace 2025The amplitude of a damped harmonic oscilator becomes 50 % of its initial value in a time of 12 s. If the amplitude of the oscillator at a time of 36 s is x % of its initial amplitu 2025If the function ^2 t ( t is time in second) represents a periodic motion, then the period of the motion is 2025 Full Oscillations list All MHT CET PYQs