MHT CET202410 May 2024Morning ShiftPhysicsOscillationsActual
A particle performing S.H.M. with maximum velocity ' V '. If the amplitude double and periodic time is made, ( 1 3 )^ rd then the maximum velocity is
Options
- AV 2
- BV 3
- C6V
- D2 ~V 3
Correct answer
C. 6V
Step-by-step solution
Given: - The amplitude doubles (A^ =2 A ) . - The period becomes one-third (T^ = 1 3 T ) . Formula for Maximum Velocity: V_ =A where = 2 T . New Angular Velocity: ^ = 2 T^ = 2 1 3 T =6 / T=3 New Maximum Velocity: V_ ^ =A^ ^ =(2 A)(3 )=6 A Since the original V_ =A : V_ ^ =6 V