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MHT CET20249 May 2024Morning ShiftPhysicsOscillationsActual

In S.H.M. the displacement of a particle at an instant is Y = A 30^ , where A =40 ~cm and kinetic energy is 200 J . If force constant is 1 10^ x N / m , then x will be ( 30^ = 3 / 2 )

Options

  1. A4
  2. B3
  3. C2
  4. D1

Correct answer

A. 4

Step-by-step solution

aligned & Y=A 30^ =40 3 2 =20 3 ~cm & K.E. = 1 2 k (A^2-Y^2 ) & 200= 1 2 k ( 1600 10^4 - 1200 10^4 ) aligned aligned & 200= 1 2 k ( 400 10^4 ) & k=10000=1 10^4 & x=4 aligned

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