MHT CET20249 May 2024Morning ShiftPhysicsOscillationsActual
A particle is performing S.H.M. with an amplitude 4 cm . At the mean position the velocity of the particle is 12 ~cm / s . When the speed of the particle becomes 6 ~cm / s , the distance of the particle from mean position is
Options
- A3 ~cm
- B6 ~cm
- C2 3 ~cm
- D2 6 ~cm
Correct answer
C. 2 3 ~cm
Step-by-step solution
At mean position, v _ = A array ll & = v_ A = 12 4 =3 rad / s & Now, v= A^2- x ^2 & v ^2= ^2 ( ~A ^2- x ^2 ) & x^2=A^2- v^2 ^2 & x= 16- 36 9 = 12 =2 3 ~cm array