MHT CET20244 May 2024Evening ShiftPhysicsOscillationsActual
The maximum velocity and maximum acceleration of a particle performing a linear S.H.M. is ' ' and ' ' respectively. Then the path length of the particle is
Options
- A^2
- B^2 2 ^2
- C2 ^2
- D2 ^2
Correct answer
C. 2 ^2
Step-by-step solution
For S.H.M., Maximum velocity, = A = A ...(i) Maximum acceleration, =A ^2 aligned & =A ( A )^2= ^2 A & A= ^2 aligned Path length =2 ~A = 2 ^2