The displacement of a particle performing S.H.M. is given by Y=A [ (t .+ )] . If at t =0 , the displacement is y =2 ~cm and velocity is 2 ~cm / s , the value of amplitude A in cm is

Step-by-step solution

aligned & y=A ( t+ ) & v=A ( t+ ) & At t=0, y₀ A = & - v₀ A = .. aligned Squaring and adding (i) and (ii) y ₀^2+ v ₀^2 ^2 = A ^2 Putting y ₀=2 ~cm and v ₀=2 ~cm / s 2^2+ (2 )^2 ^2 =A^2 A=2 2