MHT CET202313 May 2023Evening ShiftPhysicsOscillationsActual
Under the influence of force ' F₁ ' the body oscillates with a period ' T ₁ ' and due to another force ' F ₂ ' body oscillates with period ' T ₂ '. If both forces acts simultaneously then the resultant period is (consider displacement is same in all three cases)
Options
- AT = T ₁^2+ T ₂^2 ~T ₁^2 ~T ₂^2
- BT = T ₁^2 ~T ₂^2 ~T ₁^2+ T ₂^2
- CT = T ₁^2 ~T ₂^2
- DT = T ₁^2+ T ₂^2
Correct answer
B. T = T ₁^2 ~T ₂^2 ~T ₁^2+ T ₂^2
Step-by-step solution
F = kx and k = m ^2 F-m ^2 x ^2= F m x For First Force, ₁^2= F ₁ mx For Second Force, ₂^2= F ₂ mx Resultant Force will be ₃^2= F ₁+ F ₂ mx ₃^2= ₁^2+ ₂^2 ₃^2 4 ^2 = ₁^2 4 ^2 + ₂^2 4 ^2 ....(dividing by 4 ^2 ) 1 ~T ₃^2 = 1 ~T ₁^2 + 1 ~T ₂^2 T ₃^2= T ₁^2 ~T ₂^2 ~T ₁^2+ T _ 2 ^2