MHT CET202311 May 2023Morning ShiftPhysicsOscillationsActual
The time period of a simple pendulum inside a stationary lift is ' T '. When the lift starts accelerating upwards with an acceleration ( g 3 ) , the time period of the pendulum will be
Options
- A5 2 ~T
- B3 2 ~T
- C2 ~T 3
- D2 ~T 5
Correct answer
B. 3 2 ~T
Step-by-step solution
Time period of a simple pendulum is T =2 ( l a ) In stationary lift, the value of acceleration is a = g T =2 ( l ~g ) When the lift is accelerating in an upward direction, there is a pseudo force acting in a downward direction. ma = mg + mg 3 a = g + g 3 a= 4 g 3 Period for a pendulum in accelerating lift is aligned T ^ & =2 l a =2 3 l 4 ~g T ^ & = 3 2 (2 l ~g ) T ^ & = 3 2 ~T aligned