Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202310 May 2023Evening ShiftPhysicsOscillationsActual

A body is executing a linear S.H.M. Its potential energies at the displacement ' x ' and ' y ' are ' E₁ ' and ' E ₂ ' respectively. Its potential energy at displacement ( x + y ) will be

Options

  1. AE ₁+ E ₂
  2. B( E ₁ + E ₂ )^2
  3. CE₁-E₂
  4. D( E₂ - E₁ )^2

Correct answer

B. ( E ₁ + E ₂ )^2

Step-by-step solution

We know, Potential Energy E _ P = 1 2 Kx ^2 E ₁= 1 2 Kx ^2 x = 2 E ₁ ~K ... (i) and E ₂= 1 2 Ky ^2 y = 2 E ₂ ~K ... (ii) Given, total displacement =(x+y) Potential energy at displacement (x+y) , E is 1 2 ~K ( x + y )^2 aligned & = 1 2 K ( 2 E₁ K + 2 E₂ K )^2 & = 1 2 K [ 2 E₁ K + 2 E₂ K +2 ( E₁ K ) ( 2 E₂ K ) ] & = ( E₁ + E₂ )^2= (E₁+E₂+2 E₁ E₂ ) aligned

Practice Oscillations on Quantrex Academy →

More from Oscillations

Force constant of interatomic bond, in a certain element, is 7.1 Nm⁻¹ . If the atom oscillates in SHM in a certain direction, what is its frequency? Given: Mole weight of the given 2026An object of mass 10g executes SHM along the x -axis with frequency of ( 10 ) Hz. At the point x = 2 cm the object has KE 1.2 J and PE 0.4 J. The amplitude of oscillation is 2026A simple pendulum of length L , mass m and electric charge q on its bob is oscillating with a time period T under uniform gravity which is in the - z direction. Upon applying a uni 2026A sphere and a cube of equal masses on a horizontal frictionless floor, are confined between two vertical walls, as shown in the figure. The cube is attached to the wall by a massl 2026A mass of 1 kg is executing SHM. Its displacement is given by x = 6.0 (100t + /4) cm. What is the maximum kinetic energy? 2026If the displacement of a particle executing simple harmonic motion is given by x =0.5 (125.6 t ) , then the time period of oscillation of the particle is nearly (Here x is displace 2025The amplitude of a damped harmonic oscilator becomes 50 % of its initial value in a time of 12 s. If the amplitude of the oscillator at a time of 36 s is x % of its initial amplitu 2025If the function ^2 t ( t is time in second) represents a periodic motion, then the period of the motion is 2025 Full Oscillations list All MHT CET PYQs