Two S.H.Ms. are represented by equations y ₁=0.1 (100 t + 3 ) and y ₂=0.1 (100 t ) The phase difference between the speeds of the two particles is

Step-by-step solution

Given: y₁=0.1 (100 t+ 3 ) and aligned y ₂= & 0.1 (100 t ) v ₁= dy ₁ dt & =0.1 100 (100 t + 3 ) v ₂= dy ₂ dt & =-0.1 100 (100 t ) & =(0.1 100 ) (100 t + 2 ) aligned Phase difference of velocity of first particle with respect to the velocity of second particle at t=0 is = ₁- ₂= 3 - 2 = - 6