MHT CET202211 Aug 2022Morning ShiftPhysicsOscillationsActual
The period of oscillation of a second's pendulum on the planet whose mass and radius are twice that of earth will
Options
- A2 ~s
- B1 2 ~s
- C1 2 ~s
- D2 2 ~s
Correct answer
D. 2 2 ~s
Step-by-step solution
Gravitational acceleration on the surface of planet of mass M and radius R is given by, g= G M R^2 Gravitational acceleration on the surface of that planet with twice mass and radius will be, g_p= G(2 M) (2 R)^2 = g_e 2 The period of oscillation of a second's pendulum on earth, T_e=2 l g_e =2 ~s The period of oscillation of a second's pendulum on planet, T_p=2 l g_p =2 2 l g_e =2 2 ~s